python算法中缀表达式转前缀并求值

发布网友发布时间：2022-05-27 16:35

共1个回答

热心网友时间：2023-11-03 22:23

#判断运算符的优先级def opOrder(op1,op2):
order_dic = {'*':4,'$':5,'/':4,'+':3,'-':3} if op1 == '(' or op2 == '(': return False
elif op2 == ')': return True
else: if order_dic[op1] < order_dic[op2]: return False
else: return Truedef infix2prefix(string):
prefix = ''
stack = []
string_tmp = ''
for s in string[::-1]: if s == '(':
string_tmp += ')'
elif s == ')':
string_tmp += '('
else:
string_tmp += s for s in string_tmp: if s.isalpha():
prefix = s + prefix else: while len(stack) and opOrder(stack[-1],s):
op = stack.pop()
prefix = op + prefix if len(stack) == 0 or s != ')':
stack.append(s) else:
stack.pop() if len(stack):
prefix = ''.join(stack) + prefix return prefixif __name__ == '__main__': for string in ['A+B*C','(A+B)*C','((A-(B+C))*D)$(E+F)']: print string,'==>',infix2prefix(string)123456789101112131415161718192021222324252627282930313233343536373839404142

输出
>>>
A+B*C ==> +A*BC
(A+B)*C ==> *+ABC
((A-(B+C))*D)$(E+F) ==> $*-A+BCD+EF1234