设u=f(x²siny,e∧xy)求du

发布网友发布时间：2024-10-24 18:11

共1个回答

热心网友时间：2024-10-28 00:05

u = f[x²siny, e∧(xy)]
u'x = 2xsinyf'1 + ye^(xy)f'2
u'y = x²cosyf'1 + xe^(xy)f'2
= [2xsinyf'1 + ye^(xy)f'2]dx + [x²cosyf'1 + xe^(xy)f'2]dy

热心网友时间：2024-10-28 00:06

u = f[x²siny, e∧(xy)]
u'x = 2xsinyf'1 + ye^(xy)f'2
u'y = x²cosyf'1 + xe^(xy)f'2
= [2xsinyf'1 + ye^(xy)f'2]dx + [x²cosyf'1 + xe^(xy)f'2]dy

热心网友时间：2024-10-28 00:06

u = f[x²siny, e∧(xy)]
u'x = 2xsinyf'1 + ye^(xy)f'2
u'y = x²cosyf'1 + xe^(xy)f'2
= [2xsinyf'1 + ye^(xy)f'2]dx + [x²cosyf'1 + xe^(xy)f'2]dy

热心网友时间：2024-10-28 00:07

u = f[x²siny, e∧(xy)]
u'x = 2xsinyf'1 + ye^(xy)f'2
u'y = x²cosyf'1 + xe^(xy)f'2
= [2xsinyf'1 + ye^(xy)f'2]dx + [x²cosyf'1 + xe^(xy)f'2]dy

声明：本网页内容为用户发布，旨在传播知识，不代表本网认同其观点，若有侵权等问题请及时与本网联系，我们将在第一时间删除处理。E-MAIL:11247931@qq.com