...平方的形式叫做配方法。阅读下列有配方法分解因式的过程
发布网友
发布时间:2024-09-24 01:31
我来回答
共4个回答
热心网友
时间:2024-10-06 06:40
(1)x^2-6x-27
=x^2-6x+9-27-9
=(x-3)^2-6^2
=(x+3)(x-9)
;(2)a^2-3a-28
=a^2-3a+9/4-28-9/4
=(a-3/2)^2-(11/2)^2
=(a+4)(x-7)
希望能帮到你,祝学习进步O(∩_∩)O,也别忘了采纳!
热心网友
时间:2024-10-06 06:40
(1)原式=(X-3)^2-3^2-27=(X-3)^2-6^2=(X-3+6)(X-3-6)=(X+3)(X-9)
(2)原式=(a-3/2)^2-(3/2)^2-28=(a-3/2)^2-(11/2)^2=(a-3/2+11/2)(a-3/2-11/2)=(a+4)(a-7)
热心网友
时间:2024-10-06 06:39
(1) x²-6x-27=x²-2·3·x+3²-36=﹙x-3﹚²-6²=﹙x-3+6﹚﹙x-3-6﹚=﹙x+3﹚﹙x-9﹚
(2)a²-3a-28=a²-2·﹙3/2﹚x+﹙3/2﹚²-9/4-28=﹙a-3/2﹚²-﹙11/2﹚²=﹙a-3/2+11/2﹚﹙a-3/2-11/2﹚=﹙a+4﹚﹙a-7﹚
热心网友
时间:2024-10-06 06:35
1)x²-6x-27
=x²-2*3x+3²-27-3²
=(x-3)²-6²
=(X-3+6)(X-3-6)
=(X+3)(X-9)
(2)a²-3a-28
=a²-2*3/2*a+(3/2)²-28-(3/2)²
=(a-3/2)²-(11/2)²
=(a-3/2-11/2)(a-3/2+11/2)
=(a+4)(x-7)
热心网友
时间:2024-10-06 06:40
(1)x^2-6x-27
=x^2-6x+9-27-9
=(x-3)^2-6^2
=(x+3)(x-9)
;(2)a^2-3a-28
=a^2-3a+9/4-28-9/4
=(a-3/2)^2-(11/2)^2
=(a+4)(x-7)
希望能帮到你,祝学习进步O(∩_∩)O,也别忘了采纳!
热心网友
时间:2024-10-06 06:36
1)x²-6x-27
=x²-2*3x+3²-27-3²
=(x-3)²-6²
=(X-3+6)(X-3-6)
=(X+3)(X-9)
(2)a²-3a-28
=a²-2*3/2*a+(3/2)²-28-(3/2)²
=(a-3/2)²-(11/2)²
=(a-3/2-11/2)(a-3/2+11/2)
=(a+4)(x-7)
热心网友
时间:2024-10-06 06:39
(1)原式=(X-3)^2-3^2-27=(X-3)^2-6^2=(X-3+6)(X-3-6)=(X+3)(X-9)
(2)原式=(a-3/2)^2-(3/2)^2-28=(a-3/2)^2-(11/2)^2=(a-3/2+11/2)(a-3/2-11/2)=(a+4)(a-7)
热心网友
时间:2024-10-06 06:38
(1) x²-6x-27=x²-2·3·x+3²-36=﹙x-3﹚²-6²=﹙x-3+6﹚﹙x-3-6﹚=﹙x+3﹚﹙x-9﹚
(2)a²-3a-28=a²-2·﹙3/2﹚x+﹙3/2﹚²-9/4-28=﹙a-3/2﹚²-﹙11/2﹚²=﹙a-3/2+11/2﹚﹙a-3/2-11/2﹚=﹙a+4﹚﹙a-7﹚