先化简,再求值。其中x=2+根号3,y=2-根号3
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发布时间:2024-09-27 06:06
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热心网友
时间:2024-09-30 23:57
原式=2/xy+(x+3)/x(x-1)÷y(x+3)(x-1)/(x-1)²
=2/xy+(x+3)/x(x-1)÷y(x+3)/(x-1)
=2/xy+(x+3)/x(x-1)*(x-1)/y(x+3)
=2/xy+1/xy
=3/xy
=3/(2+√3)(2-√3)
=3/(4-3)
=3
热心网友
时间:2024-09-30 23:55
原式=2/xy+(x+3)/x(x-1)÷y(x+3)(x-1)/(x-1)²
=2/xy+(x+3)/x(x-1)÷y(x+3)/(x-1)
=2/xy+(x+3)/x(x-1)*(x-1)/y(x+3)
=2/xy+1/xy
=3/xy
=3/(2+√3)(2-√3)
=3/(4-3)
=3