...=根号3sin^2x+sinxcosx. 求函数f(x)在区间[...
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发布时间:2024-10-02 20:20
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时间:2024-10-26 00:09
f(x)=根号3sin^2x+sinxcosx=1/2sin2x-√3/2cos2x+√3/2
=sin(2x-π/3)+√3/2
当x属于[π/2,π]时,2x-π/3属于[2π/3,5π/3]
令2x-π/3=4π/3或5π/3
得到x=5π/6或π
所以所求零点为(5π/6,0)(π,0)
(2)g(x)=sinxcosx=1/2sin2x
令2x=π/2+kπ
得到x=π/4+kπ/2
(k是整数)
故g(x)对称轴是x=π/4+kπ/2
(k是整数)