发布网友 发布时间:2022-05-08 04:30
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热心网友 时间:2023-11-26 07:59
令y=0 2x^2=3 x^2=3/2 x1=-√6/2 x2=√6/2 S=∫[-√6/2,√6/2](3-2x^2)dx =∫[-√6/2,√6/2](3)dx-∫[-√6/2,√6/2](2x^2)dx =3x|[-√6/2,√6/2] -2/3* x^3|[-√6/2,√6/2] =3√6-2/3(6√6/4) =3√6-√6 =2√6热心网友 时间:2023-11-26 07:59
令y=0 2x^2=3 x^2=3/2 x1=-√6/2 x2=√6/2 S=∫[-√6/2,√6/2](3-2x^2)dx =∫[-√6/2,√6/2](3)dx-∫[-√6/2,√6/2](2x^2)dx =3x|[-√6/2,√6/2] -2/3* x^3|[-√6/2,√6/2] =3√6-2/3(6√6/4) =3√6-√6 =2√6