判断一个字符串是否是对称字符串，例如"abc"不是对称字符串，"aba"、"abba"、"aaa"、"mnanm"是对称字符串
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发布时间：2022-04-18 19:59
共2个回答
懂视网
时间：2022-04-19 00:20
# 1.判断一字符串是不是对称的，如：abccba
def is_symmetrical(str):
length = len(str)
for index in range(length / 2):
if str[index] == str[length - index - 1]:
pass
else:
return False
return True
if __name__ == "__main__":
print is_symmertrical("abcdcba"),
print is_symmertrical("abccaa"),
运行结果: True False
# 2.用递归的方法判断整数组a[N]是不是升序排列
# index初始化为1
def is_asc(sequence, index):
if index > len(sequence) - 1:
return True
if sequence[index] > sequence[index - 1]:
return is_asc(sequence, index + 1)
return False
if __name__ == "__main__":
sequence1 = [1, 100, 100, 200]
print is_asc(sequence1, 1),
sequence2 = [1, 100, 101, 500]
print is_asc(sequence2, 1),
运行结果: False True
热心网友
时间：2022-04-18 21:28
/**
* 4、判断一个字符串是否是对称字符串，例如"abc"不是对称字符串
* ，"aba"、"abba"、"aaa"、"mnanm"是对称字符串
*
*/
public class Test4 {
public static void main(String[] args) {
// TODO Auto-generated method stub
String arrString[] = {"abc", "aba","aa","mnanm","a"};
int length = arrString.length;
for (int i = 0; i < length; i++) {
int k = arrString[i].length();
boolean stau = true;
//将字符串转化为字符数组
char[] as = arrString[i].toCharArray();
for (int j = 0; j <= k/2; j++) {
if (as[j] != as[k-j-1]) {
System.out.println("字符串\"" + arrString[i] + "\"不是对称字符串");
stau = false;
break;
}
}
if (stau) {
System.out.println("字符串\"" + arrString[i] + "\"是对称字符串");
}
}
}
}
