恒等式与因式分解4(请尽快回答)

发布网友发布时间：2023-08-28 00:51

共1个回答

热心网友时间：2024-12-02 00:45

(6+5)(5-6c)=11(5-6c)=55-66c (5c-7)(7-x)=35c-5cx-49+7x (x+2)(x-2)=x²-2x+2x-4=x²-4 (5x+2x)(5-2x)=(7x)(5-2x)=35x-14x²=-14x²+35x (x+3)(x-3)=x²-3x+3x-9=x²-9 (4x-1)(1+4x)=4x+16x²-1-4x=16x²-1
1.(x+3)(x-3) =x²-3² =x²-9 2.(4x-1)(1+4x) =(4x-1)(4x+1) =(4x)²-1² =16x²-1 3.(5x+2x)(5-2x) =25x-10x²+10x-4x² =-10x²-4x²+25x+10x =-14x²+30x =2x(-7x+15) 4.(x+2)(x-2) =x²-2² =x²-4 5.(6+5)(5-6c) =11(5-6c) =55-66c 6.(5c-7)(7-x) =35c-5cx-49+7x 2014-11-28 19:28:38 补充： 3.(5x+2x)(5-2x) =7x(5-2x) =35x-14x² =7x(5-2x)
1. (x+3)(x-3) =x^2 -9 2. (4x-1)(1+4x) =(4x-1)(4x+1) =16x^2 -1 3. (5x+2x)(5-2x) =(7x)(5-2x) =35x-14x^2 4. (x+2)(x-2) =x^2 -4 5. (6+5)(5-6c) =11(5-6c) =55-66c 6. (5c-7)(7-x) =35c-5cx-49+7x =35c-5cx+7x-49

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