写一个函数,实现计算9～99的累加和,并在主函数中调用它,把求出来的和...
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发布时间：2023-08-01 02:32
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include<stdio.h>long sum(int n){return((1+n)*n/2);}int main(){int n;printf("n=");scanf("%d",&n);printf("sum=%d\n",sum(n));return(0);}
...y,调用函数求出X,y的和,差,商,积,并在主函数中对他们输出include<stdio.h> int add(int a,int b){ return a+b;} int sub(int a,int b){ return a-b;} int mul(int a,int b){ return a*b;} float divi(int a,int b){ return 1.0*a/b;} void main(){ int x,y;scanf("%d%d",&x,&y);printf("x+y=%d\n",add(x,y));p...
js编写一个函数,计算两个数字的和、差、积、商(要求:使用传参的...这个函数返回较为精确的除法结果。 ** 调用：accDiv(arg1,arg2) ** 返回值：arg1除以arg2的精确结果 **/function accDiv(arg1, arg2) { var t1 = 0, t2 = 0, r1, r2; try { t1 = arg1.toString().split(".")[1].length; } catch (e) { } try { t2...
用递归算法编写,求1到n的累加和,在主函数中调用?源程序已经有了希望给...String.prototype.sub = function (n) { var r = /[^\x00-\xff]/g;if (this.replace(r, "mm").length <= n) return this;// n = n - 3;var m = Math.floor(n / 2);for (var i = m; i < this.length; i++) { if (this.substr(0, i).replace(r, "mm").length...
编写一个函数实现求两个数和的立方,并在主函数main()中调用该函数include"stdio.h"int li(int x,int y){ return x*x*x+y*y*y;} main(){ int a,b,sum;printf("please input a and b:");scanf("%d%d",&a,&b);sum=li(a,b);printf("sum=%d\n",sum);} 不懂留言！
...在主函数中调用该函数,并循环输出新数组的内容。static void Main(string[] args) { int[] arr = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 }; int[] newarr = OddArray(arr); foreach (int i in newarr) { Console.WriteLine(i); } Console.Read(); } public static int[] OddArray(int[]...
写一个判断素数的函数,在主函数中调用素数的判断函数,求出2到1000之间...int prime(int n){//素数判断 int i;if(n>2 && !(n&1) || n<2)return 0;for(i=3;i*i<=n;i+=2)if(!(n%i))return 0;return n;} int main(int argc,char *argv[]){ int n,s;for(s=0,n=2;n<1000;n += n!=2 ? 2 : 1)s+=prime(n);printf("The result is ...
...个字符串的连接,采用指针实现其过程,并在主函数中调用.include<stdio.h>catstr(char *str1,char *str2);main(){char s1[20]="abc",s2[]="ABC";//s1要足够大char *p1=s1,*p2=s2;catstr(p1,p2);puts(s1);//在这里输出}catstr(char *str1,char *str2){while (*str1!='\0'){ str1++;} while (*str2!='\0'){ *str...
...用递归算法编写,求1到n的累加和,在主函数中调用int n){ return (n == 1)? 1 ： n * func(n-1);} int main(void){ unsigned int n = 0, rval = 0;printf("Input data:");scanf("%u", &n);if (n == 0){ printf("Input error.\n");return -1;} rval = func(n);printf("%u!=%u\n", n, rval);return 0;} ...
...n)求m和n的乘积,在主函数中输入m和n,并在主函数解题过程如下图：
