xe^4xdx用不定积分求解
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发布时间：2023-07-27 09:15
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热心网友
时间：2024-12-02 07:43
∫ xe^4x dx (u = x, v' = e^4x, v = 1/4 e^4x)
= (1/4)xe^4x - (1/4) ∫ e^4x dx
= (1/4)xe^4x - (1/4)(1/4) e^4x + C
= (1/4)xe^4x - (1/16)e^4x + C
不明白可以追问，望采纳！
