【搜题】十字相乘的因式分解题目!!!
发布网友
发布时间:2022-05-01 12:26
我来回答
共2个回答
热心网友
时间:2023-10-12 00:22
练习
把下列各式分解因式:
1.x4-15x2+26; 2.(x+y) 2-(x+y)-2;
3.y4-26y2+25; 4.(a-b) 2+6(b-a)+5;
5.(x2-2x)2-7(x2-2x)-8; 6.x2-2xy-8y2;
7.x2+(a+b)x+ab; 8.x4-7x2y2+6y4;
答案:
1.(x2-13)(x2-2); 2.(x+y+1)(x+y-2);
3.(y+5)(y-5)(y+1)(y-1); 4.(a-b-1)(a-b-5);
5.(x-4)(x+2)(x-1) 2; 6.(x+2y)(x-4y);
7.(x+a)(x+b); 8.(x+y)(x-y)(x2-6y2);
小结
把下列各式分解因式:
1.(1)x4+7x2-18; (2)x6+8x3+15;
(3)m2x2-8mx+12; (4)x2y2-7xy+10;
2.(1)x2-7xy+12y2; (2)a2+2ab-15b2;
(3)m2+4mn-12n2; (4)p2+9pq+18q2.
3.(1)(m+n) 2-(m+n)-30; (2)(x-y) 2-3(x-y)-40;
(3)(2m+n) 2-4r(2m+n)+3r2; (4)(a-b) 2-12(a-b)-45.
4.(1)(x2-4x) 2-(x2-4x)-20; (2)(a2+5a+3)(a2+5a-2)-6.
答案:
1.(1)(x2-2)(x2+9); (2)(x2+3)(x3+5);
(3)(mx-2)(mx-6); (4)(xy-2)(xy-5).
2.(1)(x-3y)(x-4y); (2)(a+5b)(a-3b);
(3)(m-2n)(m+6n); (4)(p+3q)(p+6q).
3.(1)(m+n-6)(m+n+5); (2)(x-y+5)(x-y-8);
(3)(2m+n-r)(2m+n-3r); (4)(a-b-15)(a-b+3).
4.(1)(x+1)(x-5)(x-2) 2;
(2) (a2+5a+3)(a2+5a-4)-6
=[(a2+5a)+3][(a2+5a)-2]-6
=(a2+5a) 2+(a2+5a)-12
=(a2+5a+4)(a2+5a-3)
=(a+1)(a+4))(a2+5a-3).
可以吗?
热心网友
时间:2023-10-12 00:22
1.用十字相乘法分解因式:
(1)2x2-5x-12; (2)3x2-5x-2;
(3)6x2-13x+5; (4)7x2-19x-6;
(5)12x2-13x+3; (6)4x2+24x+27.
2.把下列各式分解因式:
(1)6x2-13xy+6y2; (2)8x2y2+6xy-35;
(3)18x2-21xy+5y2; (4)2(a+b) 2+(a+b)(a-b)-6(a-b) 2.
答案:
1.(1)(x-4)(2x+3); (2)(x-2)(3x+1);
(3)(2x-1)(3x-5); (4)(x-3)(7x+2);
(5)(3x-1)(4x-3); (6)(2x+3)(2x+9).
2.(1)(2x-3y)(3x-2y); (2)(2xy+5)(4xy-7);
(3)(3x-y)(6x-5y); (4)(3a-b)(5b-a).
1.用十字相乘法分解因式:
(1)2x2+3x+1; (2)2y2+y-6;
(3)6x2-13x+6; (4)3a2-7a-6;
(5)6x2-11xy+3y2; (6)4m2+8mn+3n2;
(7)10x2-21xy+2y2; (8)8m2-22mn+15n2.
2.把下列各式分解因式:
(1)4n2+4n-15; (2)6a2+a-35;
(3)5x2-8x-13; (4)4x2+15x+9
(5)15x2+x-2; (6)6y2+19y+10;
(7)20-9y-20y2; (8)7(x-1) 2+4(x-1)(y+2)-20(y+2) 2.
答案:
1.(1)(2x+1)(x+1); (2)(y+2)(2y-3);
(3)(2x-3)(3x-2); (4)(a-3)(3a+2);
(5)(2x-3y)(3x-y); (6)(2m+n)(2m+3n);
(7)(x-2y)(10x-y); (8)(2m-3n)(4m-5n).
2.(1)(2n-3)(2n+5); (2)(2a+5)(3a-7);
(3)(x+1)(5x-13); (4)(x+3)(4x+3);
(5)(3x-1)(5x+2); (6)(2y+5)(3y+2);
(7)-(4y+5)(5y-4); (8)(x+2y+3)(7x-10y-27).
参考资料:http://www.cbe21.com/subject/maths/printer.php?article_id=269
热心网友
时间:2023-10-12 00:22
练习
把下列各式分解因式:
1.x4-15x2+26; 2.(x+y) 2-(x+y)-2;
3.y4-26y2+25; 4.(a-b) 2+6(b-a)+5;
5.(x2-2x)2-7(x2-2x)-8; 6.x2-2xy-8y2;
7.x2+(a+b)x+ab; 8.x4-7x2y2+6y4;
答案:
1.(x2-13)(x2-2); 2.(x+y+1)(x+y-2);
3.(y+5)(y-5)(y+1)(y-1); 4.(a-b-1)(a-b-5);
5.(x-4)(x+2)(x-1) 2; 6.(x+2y)(x-4y);
7.(x+a)(x+b); 8.(x+y)(x-y)(x2-6y2);
小结
把下列各式分解因式:
1.(1)x4+7x2-18; (2)x6+8x3+15;
(3)m2x2-8mx+12; (4)x2y2-7xy+10;
2.(1)x2-7xy+12y2; (2)a2+2ab-15b2;
(3)m2+4mn-12n2; (4)p2+9pq+18q2.
3.(1)(m+n) 2-(m+n)-30; (2)(x-y) 2-3(x-y)-40;
(3)(2m+n) 2-4r(2m+n)+3r2; (4)(a-b) 2-12(a-b)-45.
4.(1)(x2-4x) 2-(x2-4x)-20; (2)(a2+5a+3)(a2+5a-2)-6.
答案:
1.(1)(x2-2)(x2+9); (2)(x2+3)(x3+5);
(3)(mx-2)(mx-6); (4)(xy-2)(xy-5).
2.(1)(x-3y)(x-4y); (2)(a+5b)(a-3b);
(3)(m-2n)(m+6n); (4)(p+3q)(p+6q).
3.(1)(m+n-6)(m+n+5); (2)(x-y+5)(x-y-8);
(3)(2m+n-r)(2m+n-3r); (4)(a-b-15)(a-b+3).
4.(1)(x+1)(x-5)(x-2) 2;
(2) (a2+5a+3)(a2+5a-4)-6
=[(a2+5a)+3][(a2+5a)-2]-6
=(a2+5a) 2+(a2+5a)-12
=(a2+5a+4)(a2+5a-3)
=(a+1)(a+4))(a2+5a-3).
可以吗?
热心网友
时间:2023-10-12 00:22
1.用十字相乘法分解因式:
(1)2x2-5x-12; (2)3x2-5x-2;
(3)6x2-13x+5; (4)7x2-19x-6;
(5)12x2-13x+3; (6)4x2+24x+27.
2.把下列各式分解因式:
(1)6x2-13xy+6y2; (2)8x2y2+6xy-35;
(3)18x2-21xy+5y2; (4)2(a+b) 2+(a+b)(a-b)-6(a-b) 2.
答案:
1.(1)(x-4)(2x+3); (2)(x-2)(3x+1);
(3)(2x-1)(3x-5); (4)(x-3)(7x+2);
(5)(3x-1)(4x-3); (6)(2x+3)(2x+9).
2.(1)(2x-3y)(3x-2y); (2)(2xy+5)(4xy-7);
(3)(3x-y)(6x-5y); (4)(3a-b)(5b-a).
1.用十字相乘法分解因式:
(1)2x2+3x+1; (2)2y2+y-6;
(3)6x2-13x+6; (4)3a2-7a-6;
(5)6x2-11xy+3y2; (6)4m2+8mn+3n2;
(7)10x2-21xy+2y2; (8)8m2-22mn+15n2.
2.把下列各式分解因式:
(1)4n2+4n-15; (2)6a2+a-35;
(3)5x2-8x-13; (4)4x2+15x+9
(5)15x2+x-2; (6)6y2+19y+10;
(7)20-9y-20y2; (8)7(x-1) 2+4(x-1)(y+2)-20(y+2) 2.
答案:
1.(1)(2x+1)(x+1); (2)(y+2)(2y-3);
(3)(2x-3)(3x-2); (4)(a-3)(3a+2);
(5)(2x-3y)(3x-y); (6)(2m+n)(2m+3n);
(7)(x-2y)(10x-y); (8)(2m-3n)(4m-5n).
2.(1)(2n-3)(2n+5); (2)(2a+5)(3a-7);
(3)(x+1)(5x-13); (4)(x+3)(4x+3);
(5)(3x-1)(5x+2); (6)(2y+5)(3y+2);
(7)-(4y+5)(5y-4); (8)(x+2y+3)(7x-10y-27).
参考资料:http://www.cbe21.com/subject/maths/printer.php?article_id=269