VB 问题~请教!!
发布网友
发布时间：2022-05-01 21:19
共4个回答
热心网友
时间：2022-06-23 16:01
Option Explicit
' 表达式计算
Public Function js(GS As String) As String
Dim i, n As Integer
Dim TempGs, Temp As String
Dim Vl() As String '操作数
Dim Vls As Integer '操作数的数目
Dim Si As Integer '上一操作符的位置
Dim Ads, Sus, Mus, Bys, Lks, Rks As Integer '操作符的数目
Dim Adp(), Mup(), Byp(), Lkp(), Rkp() As Integer '操作符的位置
Dim Adn(), Mun(), Byn() As Integer '操作符的排列次序
Dim Sig() As Integer '每一个操作符的位置
On Error GoTo Err
Do While True
ReDim Adp(Len(GS)), Mup(Len(GS)), Byp(Len(GS)) _
, Lkp(Len(GS)), Rkp(Len(GS)) As Integer
ReDim Adn(Len(GS)), Mun(Len(GS)), Byn(Len(GS)) _
, Lkn(Len(GS)), Rkn(Len(GS)), Sig(Len(GS)) As Integer
ReDim Vl(Len(GS))
If Len(GS) = 0 Then GoTo Err
If Mid(GS, Len(GS), 1) <> "#" Then
TempGs = GS
For i = 1 To Len(GS) '将减化加
If Mid(GS, i, 1) = "-" And i <> 1 Then
If Mid(GS, i - 1, 1) <> "+" And Mid(GS, i - 1, 1) <> "-" _
And Mid(GS, i - 1, 1) <> "*" And Mid(GS, i - 1, 1) <> "/" Then
TempGs = Mid(TempGs, 1, i - 1 + n) + "+" + Mid(GS, i)
n = n + 1
End If
End If
Next i
GS = TempGs
n = 0
For i = 1 To Len(GS) '处理负负得正
If Mid(GS, i, 1) = "-" Then
If Mid(GS, i + 1, 1) = "-" Then
TempGs = Mid(TempGs, 1, i - 1 - n) + Mid(GS, i + 2)
n = n + 2
End If
End If
Next i
GS = TempGs
GS = GS + "#"
End If
Vls = 1
Ads = 0: Sus = 0: Mus = 0: Bys = 0: Lks = 0: Rks = 0
For i = 1 To Len(GS)
Select Case Mid(GS, i, 1)
Case "+"
Ads = Ads + 1
Adp(Ads) = i
Adn(Ads) = Vls
Case "*"
Mus = Mus + 1
Mup(Mus) = i
Mun(Mus) = Vls
Case "/"
Bys = Bys + 1
Byp(Bys) = i
Byn(Bys) = Vls
Case "("
Lks = Lks + 1
Lkp(Lks) = i
Case ")"
Rks = Rks + 1
Rkp(Rks) = i
End Select
If Mid(GS, i, 1) = "+" Or Mid(GS, i, 1) = "*" Or _
Mid(GS, i, 1) = "/" Or Mid(GS, i, 1) = "#" Then
If Si + 1 = i And Mid(GS, i + 1, 1) <> "#" _
Then '操作符非法连续或以操作符开头
GoTo Err
Else
Si = i
End If
If Not IsNumeric(Vl(Vls)) And Mid(GS, i + 1, 1) <> "#" _
Then '操作数不是数字
GoTo Err
End If
Sig(Vls) = i
Vls = Vls + 1
Else
If Mid(GS, i, 1) <> "(" And Mid(GS, i, 1) <> ")" Then
Vl(Vls) = Vl(Vls) + Mid(GS, i, 1) '制作操作数
Else
If i <> 1 Then
If ((Mid(GS, i - 1, 1) = "(" And Mid(GS, i, 1) = ")") Or _
(Mid(GS, i - 1, 1) = ")" And Mid(GS, i, 1) = "(")) _
Then '判定括号前后符号的合法性
GoTo Err
End If
End If
End If
End If
Next i
If Lks <> Rks Then
GoTo Err '左右括号数是否匹配
End If
For i = 1 To Lks
If Lkp(i) > Rkp(i) Then GoTo Err '左右括号出现顺序错误
Next i
If Lks <> 0 Then '括号处理
Do While True
For i = Lks To 1 Step -1
For n = Rks To 1 Step -1
Temp = js(Mid(GS, Lkp(i) + 1, Rkp(n) - Lkp(i) - 1))
If Temp <> "公式有错误" Then
GS = Mid(GS, 1, Lkp(i) - 1) + Temp + Mid(GS, Rkp(n) + 1)
Exit Do
End If
Next n
Next i
If Temp = "公式有错误" Then GoTo Err
'括号中有错误退出
Loop
Else
If Mus <> 0 Then '乘法处理
GS = Mid(GS, 1, Sig(Mun(1) - 1)) + Trim(Str(Val(Vl(Mun(1))) _
* Val(Vl(Mun(1) + 1)))) + Mid(GS, Val(Mup(1)) + Len(Vl(Mun(1) _
+ 1)) + 1)
Else
If Bys <> 0 Then '除法处理
GS = Mid(GS, 1, Sig(Byn(1) - 1)) + Trim(Str(Val(Vl(Byn(1))) _
/ Val(Vl(Byn(1) + 1)))) + Mid(GS, Val(Byp(1)) + Len(Vl(Byn(1) _
+ 1)) + 1)
Else
If Ads <> 0 Then '加法处理
GS = Trim(Str(Val(Vl(1)) + Val(Vl(2)))) + Mid(GS, Val(Adp(1)) _
+ Len(Vl(2)) + 1)
Else
js = Mid(GS, 1, Len(GS) - 1)
Exit Function
End If
End If
End If
End If
Loop
Err:
js = "公式有错误"
End Function
Private Sub Command1_Click()
If Text1.Text = "2" Then
Call TestFile(App.Path & "\1.cfg")
End If
End Sub
Private Sub TestFile(FileName As String)
If Dir(FileName) = "" Then
MsgBox "文件不存在！"
Exit Sub
End If
Dim i As Integer, j As Integer, k As Integer, S As String, BakFile As String
BakFile = App.Path & "\~tmp.dat"
If Dir(BakFile) <> "" Then Kill BakFile
i = FreeFile
Open FileName For Input As #i
j = FreeFile
Open BakFile For Output As #j
Do While Not EOF(i)
Line Input #i, S
k = InStr(S, "=")
If k > 0 Then
Print #j, Left(S, k) & js(Left(S, k - 1))
End If
Loop
Close #i, #j
Kill FileName
Name BakFile As FileName
MsgBox "文件检查成功！"
End Sub
热心网友
时间：2022-06-23 16:01
文件操作方面的一些例子 供参考
Open "TESTFILE" For Output As #1 ' 打开输出文件。
Print #1, "This is a test" ' 将文本数据写入文件。
Print #1, ' 将空白行写入文件。
Print #1, "Zone 1"； Tab ； "Zone 2" ' 数据写入两个区（print zones）。
Print #1, "Hello" ； " " ； "World" ' 以空格隔开两个字符串。
Print #1, Spc(5) ； "5 leading spaces " ' 在字符串之前写入五个空格。
Print #1, Tab(10) ； "Hello" ' 将数据写在第十列。
热心网友
时间：2022-06-23 16:02
热心网友
时间：2022-06-23 16:02
