python字节转换

发布网友发布时间：2022-05-01 00:32

共1个回答

热心网友时间：2022-06-21 10:10

import struct
struct.pack("i", 200).encode('hex')
struct.pack("f", 3.14).encode('hex')
'hello'.encode('hex')

struct.unpack('i','c8000000'.decode('hex'))[0]
round(struct.unpack('f','c3f54840'.decode('hex'))[0],5)
'68656c6c6f'.decode('hex')
'{%s}' % ','.join([str(int(i,16)) for i in re.findall(r'.{2}','68656c6c6f')])
''.join([hex(int(i))[2:] for i in re.findall(r'\d+','{104,101,108,108,111}')])

Python 2.7.12 (default, Nov 22 2016, 17:23:24)

[GCC 4.4.7 20120313 (Red Hat 4.4.7-17)] on linux2

Type "copyright", "credits" or "license()" for more information.

>>> import struct

>>> struct.pack("f", 3.14).encode('hex')

'c3f54840'

>>> round(struct.unpack('f','c3f54840'.decode('hex'))[0],5)

3.14

>>> struct.pack("i", 200).encode('hex')

'c8000000'

>>> struct.unpack('i','c8000000'.decode('hex'))[0]

200

>>> '68656c6c6f'.decode('hex')

'hello'

>>> 'hello'.encode('hex')

'68656c6c6f'

>>> import re

>>> '{%s}' % ','.join([str(int(i,16)) for i in re.findall(r'.{2}','68656c6c6f')])

'{104,101,108,108,111}'

>>> ''.join([hex(int(i))[2:] for i in re.findall(r'\d+','{104,101,108,108,111}')])

'68656c6c6f'