Python使用Ctypes调用lib,怎么使用指针类型参数接收输出参数

发布网友发布时间：2022-05-06 05:44

共1个回答

热心网友时间：2022-04-18 23:17

本文演示了在python中调用C语言生成的动态库，返回结构体指针，并进行输出！

test.c(动态库源代码)
// 编译生成动态库: gcc -g -fPIC -shared -o libtest.so test.c

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

typedef struct StructPointerTest
{
char name[20];
int age;
}StructPointerTest, *StructPointer;

StructPointer test()// 返回结构体指针
{
StructPointer p = (StructPointer)malloc(sizeof(StructPointerTest));
strcpy(p->name, "Joe");
p->age = 20;

return p;
}
编译：gcc -g -fPIC -shared -o libtest.so test.c

call.py(python调用C语言生成的动态库):
#!/bin/env python
# coding=UTF-8

from ctypes import *

#python中结构体定义
class StructPointer(Structure):
_fields_ = [("name", c_char * 20), ("age", c_int)]

if __name__ == "__main__":
lib = cdll.LoadLibrary("./libtest.so")
lib.test.restype = POINTER(StructPointer)
p = lib.test()

print "%s: %d" %(p.contents.name, p.contents.age)

最后运行结果：
[zcm@c_py #112]$make clean
rm -f *.o libtest.so
[zcm@c_py #113]$make
gcc -g -fPIC -shared -o libtest.so test.c
[zcm@c_py #114]$./call.py
Joe: 20
[zcm@c_py #115]$