如图,直线ab,cd相交于点o,oe平分∠bod,of平分∠cow,∠aod:∠boe=7:1...
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发布时间：2024-02-09 16:55
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时间：2024-10-31 09:28
∴∠AOD=7∠BOE
又OE平分∠BOD
∴∠BOD=2∠BOE
又∠AOD+∠BOD=180°
∴7∠BOE+2∠BOE=180°
解之得：∠BOE=20°
∴∠BOD=2*20°
=40°
∴∠BOC=180°-∠BOD
=180°-40°
=140°
又OF平分∠COE
∴∠COF=(∠BOC+20°)/2
=(140°+20°)/2
=80°
∴∠BOF=80°-20°
=60°
又∠AOF+∠BOF=180°
∴∠AOF=180°-∠BOF
=180°-60°
=120°
