发布网友 发布时间:2022-05-02 17:34
共3个回答
懂视网 时间:2022-05-12 05:09
原理:使用DeviceMotion实现,关于DeviceMotion介绍可以查看通过DeviceMotionEvent,可以获得accelerationIncludingGravity的x,y,z属性,根据x,y,z属性的变化来判断设备是否有摇一摇的事件发生。
accelerationIncludeingGravity说明:
The acceleration of the device. This value includes the effect of gravity, and may be the only value available on devices that don’t have a gyroscope to allow them to properly remove gravity from the data.
代码如下:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"><html> <head> <meta http-equiv="content-type" content="text/html;charset=utf-8"> <title> html5使用DeviceMotionEvent实现摇一摇 </title> <style type="text/css"> .center{position:absolute; width:640px; height:480px; left:50%; top:50%; margin-left:-320px; margin-top:-240px; line-height:480px; text-align:center; font-size:100px; } .normal{background:#000000;} .normal .txt{color:#FFFFFF;} .doing{background:#FF0000;} .doing .txt{color:#FFFF00;} </style> </head> <body id="mybody" class="normal"> <p id="txt" class="txt center">请执行摇一摇</p> </body> <script type="text/javascript"> var doing = 0; // 判断是否在动画显示中 var speed = 23; // 定义摇动的速度数值 var lastx = 0; var lasty = 0; var lastz = 0; function handleMotionEvent(event) { var x = event.accelerationIncludingGravity.x; var y = event.accelerationIncludingGravity.y; var z = event.accelerationIncludingGravity.z; if(doing==0){ if(Math.abs(x-lastx)>speed || Math.abs(y-lasty)>speed){ doing = 1; show(); } } lastx = x; lasty = y; lastz = z; } function show(){ document.getElementById('mybody').className = 'doing'; document.getElementById('txt').innerHTML = '执行了摇一摇'; setTimeout(function(){ doing=0; document.getElementById('mybody').className='normal'; document.getElementById('txt').innerHTML = '请执行摇一摇'; },3000); } window.addEventListener("devicemotion", handleMotionEvent, true); </script></html>
本文介绍了通过html5实现摇一摇的功能,更多相关内容请关注Gxl网。
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热心网友 时间:2022-05-12 02:17
HTML5 有很多强大的功能,比如获取设备的 x y z 坐标。这些值都可以通过代码获取并呈现出来。热心网友 时间:2022-05-12 03:35
settimeout