用Python编程,两个乒乓球队进行比赛问题

发布网友发布时间：2022-05-04 11:43

共2个回答

热心网友时间：2022-06-21 13:37

m=['a','b','c']
n=['x','y','z']
t=[]
for i in m:
    for g in n:
        t.append(i)
        t.append(g)
        if  t[0]=='a' and t[1]!='x'  :
            print(t[0],t[1])
        if  t[0]=='b':
            print(t[0],t[1])
        if t[0]=='c'and t[1]!='x'and t[1]!='z':
            print(t[0],t[1])
        t=[]

热心网友时间：2022-06-21 13:37

for player1 in 'abc':
    for player2 in 'xyz':
        if (player1 == 'a' and player2 != 'x') or \
           (player1 == 'c' and player2 not in 'xz'):
            print("{}----{}\n".format(player1, player2))

追问

可是运行出来的结果是 : a----y a----z c----y ,您能帮我解决一下吗？

追答for player1 in 'cab':
    for player2 in 'xyz':
        if player1 == 'c' and player2 not in 'xz':
            remain2 = set('xyz') - set(player2)
            print("{}----{}\n".format(player1,player2))
        if player1 == 'a' and player2 != 'x' and player2 in remain2:
            remain2 -= set(player2)
            print("{}----{}\n".format(player1,player2))
        if player1 == 'b' and player2 in remain2:
            print("{}----{}\n".format(player1,player2))