编一程序,生成并显示20个【200,300】区间的随机整数,然后再逆序显示

发布网友发布时间：2022-07-29 03:01

共2个回答

热心网友时间：2023-11-18 05:52

java程序代码如下：

public class RandomSort {

public int [] numArray = new int[20];

public RandomSort(){

  for (int i = 0; i < 20; i++){

   this.numArray[i] = ((int)(Math.random() * 100 + 200));
  }
}
//快速排序方法
public int[] SortFunction(int[] array){

  int i = 0;
  int j = 0; //
  int k = 0;

  int temp = 0;
  for(i = 0; i < array.length - 1; i++){

   j = array.length - 1;

   k = array[i];

   for(; j > i; j--){

    if(array[j] < k ){

     k = array[j];

     temp = array[i];

     array[i] = array[j];

     array[j] = temp;
    }
   }

  }

  return array;
}

public static void main(String[] args) {

  RandomSort random1 = new RandomSort();

  int[] array = random1.SortFunction(random1.numArray);

  System.out.println("20个随机数：");

  for(int i = 0; i < random1.numArray.length; i++){

   System.out.print(random1.numArray[i] + ";");
  }

  System.out.println("");

  System.out.println("逆序显示结果：");

  for(int j = array.length - 1; j >= 0; j--){

   System.out.print(array[j] + ";");
  }
}

}
结果如下图：

热心网友时间：2023-11-18 05:52

#include<stdio.h>

#include<time.h>

#define N 20

void main()

{ int i,j,k,a[N];

srand((unsigned int)time(NULL));

for ( i=0;i<N;i++ ) a[i]=rand()%101+200;

for ( i=0;i<N-1;i++ ) for ( j=i+1;j<N;j++ ) if ( a[i]<a[j] ) { k=a[i]; a[i]=a[j]; a[j]=k; }

for ( i=0;i<N;i++ ) printf("%d ",a[i]); printf("\n");

}