100分求两条通达信的公式,高手进。
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发布时间:2022-10-20 04:31
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时间:2024-11-18 01:53
MA1:=MA(CLOSE,10);
MA2:=MA(CLOSE,20);
MA3:=MA(CLOSE,30);
MA4:=MA(CLOSE,60);
T1:=LAST(MA1<REF(MA1,1) AND MA2<REF(MA2,1) AND MA3<REF(MA3,1) AND MA4<REF(MA4,1),3,0);
T2:=(REF(C,2)-REF(C,1))/REF(C,1)>0.03;
T3:=O<REF(C,1) AND ABS((C-O)/O)<0.015;
XG:T1 AND T2 AND T3;
MA1:=MA(CLOSE,10);
MA2:=MA(CLOSE,20);
MA3:=MA(CLOSE,30);
MA4:=MA(CLOSE,60);
T1:=LAST(MA1<REF(MA1,1) AND MA2<REF(MA2,1) AND MA3<REF(MA3,1) AND MA4<REF(MA4,1),3,0);
T2:=REF(C,1)<REF(C,2);
T3:=O<REF(C,1) AND C>O;
XG:T1 AND T2 AND T3;