%E4%BC%A0%E5%A5%87%E7%A7%81%E6%9C%8D 这种类型的代码 是什么码,怎么能转换成正常的?求大神指点。
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发布时间:2022-11-05 02:32
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热心网友
时间:2023-10-04 02:04
这个叫做url encoding,即URL编码,在网址上或者POST数据的时候用,目的是防止文字内容里面的=、?等特殊字符干扰query string的结构,避免解析错误
你给出的“%E4%BC%A0%E5%A5%87%E7%A7%81%E6%9C%8D”解码后就是汉字“传奇私服”
在百度上搜索“url encode”能找到这种编码的在线解析应用
Java语言使用apache commons codec库也可以对其进行编码或解码
C语言中可手动实现编码与解码:
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
#include <sys/types.h>
#include "url.h"
static unsigned char hexchars[] = "0123456789ABCDEF";
static int php_htoi(char *s)
{
int value;
int c;
c = ((unsigned char *)s)[0];
if (isupper(c))
c = tolower(c);
value = (c >= '0' && c <= '9' ? c - '0' : c - 'a' + 10) * 16;
c = ((unsigned char *)s)[1];
if (isupper(c))
c = tolower(c);
value += c >= '0' && c <= '9' ? c - '0' : c - 'a' + 10;
return (value);
}
char *php_url_encode(char const *s, int len, int *new_length)
{
register unsigned char c;
unsigned char *to, *start;
unsigned char const *from, *end;
from = (unsigned char *)s;
end = (unsigned char *)s + len;
start = to = (unsigned char *) calloc(1, 3*len+1);
while (from < end)
{
c = *from++;
if (c == ' ')
{
*to++ = '+';
}
else if ((c < '0' && c != '-' && c != '.') ||
(c < 'A' && c > '9') ||
(c > 'Z' && c < 'a' && c != '_') ||
(c > 'z'))
{
to[0] = '%';
to[1] = hexchars[c >> 4];
to[2] = hexchars[c & 15];
to += 3;
}
else
{
*to++ = c;
}
}
*to = 0;
if (new_length)
{
*new_length = to - start;
}
return (char *) start;
}
int php_url_decode(char *str, int len)
{
char *dest = str;
char *data = str;
while (len--)
{
if (*data == '+')
{
*dest = ' ';
}
else if (*data == '%' && len >= 2 && isxdigit((int) *(data + 1)) && isxdigit((int) *(data + 2)))
{
*dest = (char) php_htoi(data + 1);
data += 2;
len -= 2;
}
else
{
*dest = *data;
}
data++;
dest++;
}
*dest = '/0';
// *dest =0; 用这个好些
return dest - str;
}