发布网友 发布时间:2022-08-19 18:37
共3个回答
热心网友 时间:2023-10-26 10:15
人家问的就是解析解,不知道上边几个在说什么追答第一组:{x(t) = _C2*exp(a*t)},
{y(t) = 0},
{z(t) = _C1*exp(Int(c*A*x(t)+P-M, t))}],
第二组:{x(t) = _C1*exp(a*t)},
{diff(y(t), t, t) = (2*e*y(t)^3*E*b*Q*x(t)*T-y(t)^2*Zm*b^2*Q^2*x(t)^3*c*A-2*y(t)^2*Zm*b*Q*x(t)*M*S+2*y(t)^2*Zm*b*Q*x(t)*P*T-2*y(t)^2*Zm*b*Q*x(t)*M*T+2*y(t)^2*Zm*b*Q*x(t)*P*S-2*y(t)^2*Zm*S*x(t)*c*A*T-y(t)*Zm*(diff(y(t), t))*b*Q*x(t)*M+y(t)*Zm*(diff(y(t), t))*b*Q*x(t)*P-y(t)*Zm*(diff(y(t), t))*x(t)*c*A*T-y(t)*Zm*(diff(y(t), t))*x(t)*c*A*S+Zm*(diff(y(t), t))*y(t)*b*Q*a*x(t)-e*y(t)^3*E*b^2*Q^2*x(t)^2+y(t)^2*Zm*b^2*Q^2*x(t)^2*M-y(t)^2*Zm*b^2*Q^2*x(t)^2*P-y(t)^2*Zm*S^2*x(t)*c*A-y(t)^2*Zm*T^2*x(t)*c*A-Zm*(diff(y(t), t))^2*S-Zm*(diff(y(t), t))^2*T+y(t)^2*Zm*S^2*M-y(t)^2*Zm*S^2*P-y(t)^2*Zm*T^2*P+y(t)^2*Zm*T^2*M-e*y(t)^3*E*S^2-e*y(t)^3*E*T^2+Zm*(diff(y(t), t))^2*b*Q*x(t)-2*e*y(t)^3*E*S*T+y(t)*Zm*(diff(y(t), t))*M*S-y(t)*Zm*(diff(y(t), t))*P*T+y(t)*Zm*(diff(y(t), t))*M*T-y(t)*Zm*(diff(y(t), t))*P*S-2*y(t)^2*Zm*S*P*T+2*y(t)^2*Zm*S*M*T+2*e*y(t)^3*E*b*Q*x(t)*S+y(t)*Zm*(diff(y(t), t))*b*Q*c*A*x(t)^2+2*y(t)^2*Zm*b*Q*x(t)^2*c*A*T+2*y(t)^2*Zm*b*Q*x(t)^2*c*A*S)/(y(t)*b*Q*x(t)*Zm-y(t)*S*Zm-y(t)*T*Zm)}
{z(t) = (-(diff(y(t), t))*Zm+y(t)*b*Q*x(t)*Zm-y(t)*S*Zm-y(t)*T*Zm)/(y(t)*b*Q*x(t)-y(t)*S-y(t)*T)}]
你如果把参数都给出来(而不是只告诉我那是一个常量字母),可以很方便的求数值解
热心网友 时间:2023-10-26 10:15
上面的都说的很对,你的方程组不能使用dsolve来求解。你需要使用数值解法热心网友 时间:2023-10-26 10:16
不能用dsolve这个命令的,应该用ode45,或ode32,具体怎么做你可以help,或者百度