发布网友 发布时间:2023-03-09 12:39
共1个回答
热心网友 时间:2023-10-11 02:07
SELECT * FROM names;
+----+--------+
| id | name |
+----+--------+
| 1 | google |
| 2 | yahoo |
| 3 | msn |
| 4 | google |
| 5 | google |
| 6 | yahoo |
想保留最大id的话:
DELETE FROM NAMES