怎么获取httpservletrequest
发布网友
发布时间：2022-04-29 22:02
共2个回答
热心网友
时间：2022-06-23 23:25
1、request.getRequestURL()
返回的是完整的url，包括Http协议，端口号，servlet名字和映射路径，但它不包含请求参数。
2、request.getRequestURI()
得到的是request URL的部分值，并且web容器没有decode过的
3、request.getContextPath()
返回 the context of the request.
4、request.getServletPath()
返回调用servlet的部分url.
5、request.getQueryString()
返回url路径后面的查询字符串
示例：
当前url：http://localhost:8080/CarsiLogCenter_new/idpstat.jsp?action=idp.sptopn
request.getRequestURL() http://localhost:8080/CarsiLogCenter_new/idpstat.jsprequest.getRequestURI() /CarsiLogCenter_new/idpstat.jsp
request.getContextPath()/CarsiLogCenter_newrequest.getServletPath() /idpstat.jsp
request.getQueryString()action=idp.sptopn
热心网友
时间：2022-06-23 23:25
public class RequestContextListener implements ServletRequestListener {
...
...
...
public void requestInitialized(ServletRequestEvent requestEvent) {
if (!(requestEvent.getServletRequest() instanceof HttpServletRequest)) {
throw new IllegalArgumentException("");
}
HttpServletRequest request = (HttpServletRequest) requestEvent.getServletRequest();
ServletRequestAttributes attributes = new ServletRequestAttributes(request);
request.setAttribute(REQUEST_ATTRIBUTES_ATTRIBUTE, attributes);
LocaleContextHolder.setLocale(request.getLocale());
RequestContextHolder.setRequestAttributes(attributes);
}
...
...
...
}
public class ServletRequestAttributes extends AbstractRequestAttributes {
...
...
...
private final HttpServletRequest request;
...
...
...
/**
* Create a new ServletRequestAttributes instance for the given request.
* @param request current HTTP request
*/
public ServletRequestAttributes(HttpServletRequest request) {
Assert.notNull(request, "Request must not be null");
this.request = request;
}
}
2、在普通类中获取对象
HttpServletRequest request = ((ServletRequestAttributes)RequestContextHolder.getRequestAttributes()).getRequest();
