python可以写那种动态的圣诞树吗
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发布时间：2022-04-29 08:23
共2个回答
懂视网
时间：2022-04-29 12:44
python圣诞树代码
1、简单的绘制圣诞树
新建tree1.py或者直接输入下面代码运行
（推荐学习：Python教程）
#声明树的高度
height = 5
#树的雪花数，初始为1
stars = 1
#以数的高度作为循环次数
for i in range(height):
print((' ' * (height - i)) + ('*' * stars))
stars += 2
#输出树干
print((' ' * height) + '|')
2、使用turtle绘制简单圣诞树
新建tree2py，输入以下代码
#导入turtle库
import turtle
#设置屏幕大小
screen = turtle.Screen()
screen.setup(800,600)
#获取画笔并设置一些属性：圆形、红色、快
circle = turtle.Turtle()
circle.shape('circle')
circle.color('red')
circle.speed('fastest')
#抬起画笔
circle.up()
#重新获取画笔
square = turtle.Turtle()
#重新设置画笔属性：四方形、绿色、快
square.shape('square')
square.color('green')
square.speed('fastest')
#重新抬起画笔
square.up()
#跳到指定坐标位置
circle.goto(0,280)
#复制当前图形
circle.stamp()
k = 0
for i in range(1, 17):
y = 30*i
for j in range(i-k):
x = 30*j
square.goto(x,-y+280)
square.stamp()
square.goto(-x,-y+280)
square.stamp()
if i % 4 == 0:
x = 30*(j+1)
circle.color('red')
circle.goto(-x,-y+280)
circle.stamp()
circle.goto(x,-y+280)
circle.stamp()
k += 2
if i % 4 == 3:
x = 30*(j+1)
circle.color('yellow')
circle.goto(-x,-y+280)
circle.stamp()
circle.goto(x,-y+280)
circle.stamp()
square.color('brown')
for i in range(17,20):
y = 30*i
for j in range(3):
x = 30*j
square.goto(x,-y+280)
square.stamp()
square.goto(-x,-y+280)
square.stamp()
turtle.exitonclick()运行：
3、使用Turtle绘制复杂圣诞树
新建tree3.py，输入以下代码
#导入所依赖的库
from turtle import *
import random
import time
n = 80.0
#设置速度快
speed("fastest")
#背景颜色 海贝壳色，偏粉色
screensize(bg='seashell')
left(90)
forward(3*n)
color("orange", "yellow")
begin_fill()
left(126)
for i in range(5):
forward(n/5)
right(144)
forward(n/5)
left(72)
end_fill()
right(126)
color("dark green")
backward(n*4.8)
def tree(d, s):
if d <= 0: return
forward(s)
tree(d-1, s*.8)
right(120)
tree(d-3, s*.5)
right(120)
tree(d-3, s*.5)
right(120)
backward(s)
tree(15, n)
backward(n/2)
for i in range(200):
a = 200 - 400 * random.random()
b = 10 - 20 * random.random()
up()
forward(b)
left(90)
forward(a)
down()
if random.randint(0, 1) == 0:
color('tomato')
else:
color('wheat')
circle(2)
up()
backward(a)
right(90)
backward(b)
time.sleep(60)运行：
热心网友
时间：2022-04-29 09:52
可以。
Python源代码：
from random import randint from time import sleepimport coloramafrom colorama import Fore, Back, Stylecolorama.init()rnd2 = randint(1,60)def gentree():for x in range(1,30,2):rnd1 = randint(1,rnd2)if x == 1:ch = "$"elif rnd1 % 4 == 0:ch = "o"elif rnd1 % 3 == 0:ch = "j"elif rnd1 % 5 == 0:ch = "o"elif rnd1 % 7 == 0:ch = "j"else:ch ="*"if ch == "$":print(Fore.RED +"{:^33}".format(ch * x))elif ch == "o":print(Fore.RED +"{:^33}".format(ch * x))elif ch == "j":print(Fore.YELLOW +"{:^33}".format(ch * x))else:print(Fore.GREEN +"{:^33}".format(ch * x))print("{:^33}".format('|||'))print("{:^33}".format('|||')) print("{:^33}".format(' Merry_christmas '))sleep(.24)gentree()
