日历(万年历)算法?最好是用C语言可以写出来的,说出意思就行,代码不用给了

发布网友发布时间：2022-04-27 09:48

共2个回答

热心网友时间：2023-09-23 07:31

sum = 348 for(i=0x8000; i> 0x8; i> > =1) sum += (lunarInfo[y-1900] & i) " ":" "); } printf("/n"); printf("下月N 大部分是jsp写的 m) { return( (lunarInfo[y-1900] & (0x10000> > m)) 我这有一组现成的： var lunarInfo=new Array( 0x04bd8 int m month-1); } else { printf("感谢使用然后按图索骥……关键是这组数据大意是将每年阴历月份的信息记录在一个数组内 88/n"); return;} } int runniansub(int year) { return ((year%4==0 && year%100 =0) || (year%4==0 && year%400==0)); } int week(int y month+1); } else if(x=='P' || x=='p') { rili(year x); if(x=='N' || x=='n') { rili(year (d<10) 30: 29) else return(0) } function leapMonth(y) { return(lunarInfo[y-1900] & 0xf) } function monthDays(y 0x0ada0) 提取信息的算法有： function lYearDays(y) { var i 0x06d20 0x1b255 0x0aa50 0x0a4b0 0x0a577 0x049b0 0x055b2 0x056d0 0x0b5a0 0x0dd45 0x0d520 0x0d250 0x1d0b6 0x0a4d0 0x04ad0 0x04bd7 0x096d0 0x076a3 0x05aa0 0x0d530 0x0ea65 0x0d260 0x0a4e0 0x0a6e6 0x04b60 0x05b52 0x0ad50 0x06aa0 0x07954 0x0a930 0x052b0 0x15176 0x0a5b0 0x04ba0 0x055d9 0x0ad50 0x0baa4 0x0b4a0 0x0a950 0x0cab5 0x092d0 0x025d0 0x0abb7 0x056a0 0x07552 0x0da50 0x0d4a0 0x0d954 0x0c960 0x092e0 0x096d5 0x0ab60 0x055c0 0x06b58 0x0ea50 0x074a3 0x064b0 0x04970 0x04af5 0x09570 0x0ab60 0x0af46 0x06d40 0x06a50 0x0b27a 0x0a4b0 0x0a974 0x049b0 0x095b0 0x195a6 0x0b5a0 0x0b540 0x0d558 0x0d250 0x0d4d4 0x0a4d0 0x04ad0 0x04dd5 0x096d0 0x056a0 0x05b57 0x0d950 0x0f263 0x05260 0x0a570 0x0aae4 0x04b60 0x0ab50 0x0aea6 0x06aa0 0x0e950 0x0a9a8 0x052d0 0x14573 0x0a5d0 0x04da0 0x15355 0x0b550 0x06ca0 0x0b557 0x0a950 0x0d2b2 0x092d0 0x025d0 0x1a5b4 0x056a0 0x0b550 0x1d8a6 0x0d4a0 0x0c950 0x1c8d7 0x092e0 0x186e3 0x02b60 0x05ad0 0x06e95 0x0ea50 0x0d4a0 0x06566 0x04970 0x052f2 0x09570 0x02b60 0x1ab54 0x06d40 0x06a50 0x0b4b5 0x0a4b0 0x04970 0x14977 0x095b0 0x0ada2 0x0d6a0 0x0b540 0x1d255 0x0d250 0x0a4d0 0x0a5b6 0x04ae0 0x055d2 0x09ad0 0x056a0 0x16554 0x0d950 0x0d260 0x054d5 0x0a570 0x04ae0 int d) { if((m==1)||(m==2)) { m+=12; y--; } return ((d+2*m+3*(m+1)/5+y+y/4-y/100+y/400)+1)%7; } ||| 现在网上有不少万年历的网页退出Q"); x=getch(); printf("%c/n" d); printf("%s" 1); for(i=0; i<3*s; i++ ) printf(" "); c=s; for(d=1;d<=monthday[month];d++) { if(c>6) { printf("/n"); c=0; } c++; printf("%d" month+1 month+1); printf("S M T W T F S/n"); s=week(year year p; char x; while(month>11) { month-=12; year++; } while(month<0) { year--; month+=12; } if(runniansub(year)) monthday[1]=29; printf("%d年%d月/n" c s i w int month) { int d d.da_mon-1); system("pause"); return 0; } void rili(int year d.da_day); rili(d.da_year d.da_mon d.da_year 31}; int main() { struct date d; getdate(&d); printf("今天是：%d年 %d月 %d日/n" 30 31 30 31 31 30 31 30 31 28 int); int monthday[12]={31 int int); int runniansub(int); int week(int #include <stdio.h> #include <conio.h> #include <dos.h> void rili(int 上月P 你查看它的源码就清楚了 1: 0 return(sum+leapDays(y)) } function leapDays(y) { if(leapMonth(y)) return((lunarInfo[y-1900] & 0x10000) 30: 29 ) } 明白了吧

热心网友时间：2023-09-23 07:31

以前写了一个
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#include<windows.h>
#include<conio.h>
#include<math.h>
void tiangan(int x)
{char a[][10]={"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"};
int i=x-1864;
i=i%10;
if(i>=0)
printf("\t\t%s",a[i]);
else
{while(i<0)
i=i+10;
printf("\t\t%s",a[i]);
}
}
void di(int x)
{char a[][10]={"子","丑","寅","卯","辰","巳","午","未","申","酉","戌","亥"};
int i=x-1864;
i=i%12;
if(i>=0)
printf("%s年",a[i]);
else
{while(i<0)
i=i+12;
printf("%s年",a[i]);}
}
void shengxiao(int x)
{char a[][10]={"鼠","牛","虎","兔","龙","蛇","马","羊","猴","鸡","狗","猪"};
int i=(x-1900)%12;
if(i>=0)
printf("(%s年)\n",a[i]);
else
{while(i<0)
i=i+12;
printf("(%s年)\n",a[i]);}
}
main()
{int i,y,x,day,j,s=0,sum=365,m,month,a[12]={31,28,31,30,31,30,31,31,30,31,30,31};
printf("请输入年份：");
scanf("%d",&x);
tiangan(x);
di(x);
shengxiao(x);
day=(x+(x-1)/4-(x-1)/100+(x-1)/400)%7;
if(x%100==0)
{if(x%400==0)
{a[1]++;sum++;}
}
else if(x%4==0)
{a[1]++;sum++;}
if(day==0)
day=7;
sum=sum+day;
for(i=0;i<12;i++)
{printf("%d年%d月：\n\n",x,i+1);
printf(" 周日周一周二周三周四周五周六\n");
{for(j=1;j<=a[i];j++)
{if(j==1)
for(m=0;m<day%7*5;m++)
printf(" ");
printf("%5d",j);
if((day+j)%7==0)
printf("\n");}
day=(day+a[i])%7;
printf("\n\n");}}
getch();
}