发布网友 发布时间:2022-04-29 15:23
共1个回答
热心网友 时间:2023-10-15 04:50
哔卡www.yfjgf8.com
原式=x/(x+(1-x)/(x2-1)/x))
=x/[x-x(x-1)/(x+1)(x-1)]
=x/[x-x/(x+1)]
=x/x[1-1/(x+1)]
=1/[1-1/(x+1)]
=1/[(x+1-1)/(x+1)]
=(x+1)/x
热心网友 时间:2023-10-15 04:50
哔卡www.yfjgf8.com
原式=x/(x+(1-x)/(x2-1)/x))
=x/[x-x(x-1)/(x+1)(x-1)]
=x/[x-x/(x+1)]
=x/x[1-1/(x+1)]
=1/[1-1/(x+1)]
=1/[(x+1-1)/(x+1)]
=(x+1)/x
热心网友 时间:2023-11-06 05:47
哔卡www.yfjgf8.com
原式=x/(x+(1-x)/(x2-1)/x))
=x/[x-x(x-1)/(x+1)(x-1)]
=x/[x-x/(x+1)]
=x/x[1-1/(x+1)]
=1/[1-1/(x+1)]
=1/[(x+1-1)/(x+1)]
=(x+1)/x